A pilot flew his plane 2400 miles in 8 hours flying with the wind. Flying against the wind over the same route, he returned in 10 hours what was the rate of the plane and of the wind?

Question

Ernesto Zimmerman

Mathematics

12 December, 04:00

A pilot flew his plane 2400 miles in 8 hours flying with the wind. Flying against the wind over the same route, he returned in 10 hours what was the rate of the plane and of the wind?

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Answers (1)

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Roger · Answer 1

Against wind : 2400 miles in 10 hours

With wind : 2400 miles in 8 hours

Speed of plane = x

Speed of wind = y

t=d/r

against the wind speed x-y mph

with the wind x=y mph

2400 / (x-y) = 10

2400 = 10x-10y

240 = x-y eq. 1

2400/x+y=8

2400 = 8x+8y

300 = x+y eq 2

Add eq1 & eq 2 = 740 = 2x

X = 740/2 = 370 mph for plane

300 = 370 + y

Y = 370-300 = 70 mph wind speed