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Israel Potts
Mathematics
31 October, 15:17
Evaluate the following definite integral.
10
∫ 13y / y^2-9y-22. dy
-1
+3
Answers (
1
)
Madilynn Ball
31 October, 15:38
0
33.1698
Step-by-step explanation:
10
∫ 13y / y^2-9y-22. dy
-1
Let's break down the fraction first before we integrate
13y / y^2-9y-22
= 13y / (y-11) (y+2)
=11 / (y-11) + 2 / (y+2)
Time to Integrate.
10
∫ 13y / y^2-9y-22. dy
-1
=∫ 11 / (y-11) dy + ∫ 2 / (y+2) Dy
= 11In (y-11) + 2 In (y+2)
When y = 10
= 11In (10-11) + 2In (10+2)
= 11In1 + 2In12
= 4.9698
When y = - 2
= 11In (y-11) + 2 In (y+2)
= 11In (-2-11) + 2In (-2+2)
= - 28.2
4.9698+28.2 = 33.1698
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