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26 September, 05:05

Solve. 3x2 + 4x = - 5

using quadratic equation ... ?

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Answers (1)
  1. 26 September, 05:11
    0
    3x^2 + 4x - 5 = 0

    x = [-b ±√ (b^2 - 4ac) ]/2a

    a = 3

    b = 4

    c = - 5

    x = [-4 ±√ (16 + 60) ]/6

    x = [-4 ±√76]/6

    x = [-4 ±√ (2^2 * 19) ]/6

    x = [-4 ±2√19]/6

    x = [-2 ±√19]/3

    x = [-2 + √19]/3

    x = [-2 + 4.35]/3

    x = 2.35/3

    x = 0.78 (rounded to the nearest hundredth)

    x = [-2 - ±√19]/3

    x = [-2 - 4.35]/3

    x = - 6.35/3

    x = - 2.12 (rounded to the nearest hundredth)

    ∴ x = - 2.12, 0.78 (rounded to the nearest hundredth)
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