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13 November, 16:59

The length of a rectangle is 5 ft longer than its width.

If the perimeter of the rectangle is 30 ft, find its area.

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  1. 13 November, 17:26
    0
    50 ft²

    Step-by-step explanation:

    If W is the width and L is the length, then:

    L = W + 5

    2L + 2W = 30

    Solve the system of equations with substitution or elimination. Using substitution:

    2 (W + 5) + 2W = 30

    2W + 10 + 2W = 30

    4W = 20

    W = 5

    L = 10

    The area of the rectangle is:

    A = LW

    A = 50 ft²
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