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27 August, 19:06

Which of the following represents the zeros of f (x) = 3x^3-10x^2-81x 28? Answer choices: A.) 7, - 4,1/3 B.) 7,-4, - 1/3 C.) 7,4,1/3 D.) 7,4,-1/3

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  1. 27 August, 19:33
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    The right function is f (x) = 3x^3-10x^2-81x + 28

    You can realize that 7 is a root because it is in all the answers.

    So you can divide the polynomial by x - 7. If you do it you can find that the quotient is 3x^2 + 11x - 4

    Now you can use the quadratic formula to find the other two roots.

    If you do it, you will find they are x = 1/3 and x = - 4.

    So the answer is option A) 7, - 4, 1/3

    And the polynomial can be written as (x - 7) (x + 4) (x - 1/3)
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