Find each value. Use a calculator is needed P (9,2). P (5,5). P (7,7)

The answers are:

P (9, 2) = 72

P (5, 5) = 120

P (7, 7) = 5040

These are examples of permutations. The problems are asking us to find the total number of ways an event can happen.

In the first case, P (9, 2), we are asked to find the ways that 2 things can be chosen out of a group of 9.

9 x 8 = 72

P (5, 5) = 5 x 4 x 3 x 2 x 1

P (7, 7) = 7 x 6 x 5 x 4 x 3 x 2 x 1