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16 June, 00:00

Prove using proof by contradiction: if x is an even integer, then 3x + 7 is odd

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  1. 16 June, 00:22
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    Suppose 3x + 7 is even when x is even

    then 3x + 7 = 2m where m is some integer

    3x = 2m - 7

    which means that 3x is odd because 2m - 7 must be odd

    but x is even and 3x is even so our original assumption is wrong

    So 3x - 7 must be odd when x is even.
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