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11 December, 15:56

In the △ABC, the altitude AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Answer: Case 1 : N∈ BC. It is. If the case is possible, then AB = in, BC = in Case 2 : B∈ NC. It is. If the case is possible, then AB = in, BC = in Case 3 : C∈ BN. It is. If the case is possible, then AB = in, BC =

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  1. 11 December, 16:16
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    Answer:AB = 30 in and BC = 50 in.

    We use Pythagorean theorem to solve this. Since AN is an altitude, this means that it is perpendicular to BC. This means BN and AN are the legs of one right triangle, with AB being the hypotenuse:

    18²+24² = AB²

    324 + 576 = AB²

    900 = AB²

    Take the square root of both sides:

    √900 = √AB²

    30 = AB

    NC and AN form the legs of the other right triangle, with AC being the hypotenuse:

    24²+NC² = 40²

    576 + NC² = 1600

    Subtract 576 from both sides:

    576 + NC² - 576 = 1600 - 576

    NC² = 1024

    Take the square root of both sides:

    √NC² = √1024

    NC = 32

    BC = BN + NC = 18 + 32 = 50
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