Three years ago Tom was twice as old as Jean. And in two years the sum of their ages will be 28 years. Find their present ages.

Jean is 9 years old and Tom is 15 years old.

Step-by-step explanation:

let t = Tom's present age

let j = Jean's age

Three years ago, Tom was twice as old as Jean,

t-3 = 2 (j-3)

t - 3 = 2j - 6

t = 2j - 6 + 3

t = 2j - 3

In two years the sum of their ages will be 28 years.

(t+2) + (j+2) = 28

t + j + 4 = 28

t + j = 28 - 4

t + j = 24

For their present ages, replace t with (2j-3) from the 1st statement

2j - 3 + j = 24

2j + j = 24 + 3

3j = 27

j = 27/3

j = 9 yrs is Jean's age

Find Tom's age

t = 2 (9) - 3

t = 15 yrs is Tom's age

Step-by-step explanation:

Answer:

Jean is 9 and Tom is 15.

Step-by-step explanation:

3 years ago, Tom was 12 and Jean was 6, hence Tom was twice as old as Jean.

Since that was their age 3 years ago, they are currently 15 (Tom) and 9 (Jean).

Add 2 years to each of these ages, you get 17 and 11.

17 + 11 = 28