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28 February, 16:04

Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale. if she bought 22 frames for $239, find how many of each type she bought.

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  1. 28 February, 16:11
    0
    small frames ($8) : s

    large frames ($15) : L

    Cost: 8s + 15L = 239 ⇒ 1 (8s + 15L = 239) ⇒ 8s + 15L = 239

    Quantity: s + L = 22 ⇒ - 8 (s + L = 22) ⇒ - 8s - 8 L = - 176

    7L = 63

    L = 9

    Quantity: s + L = 22 ⇒ s + (9) = 22 ⇒ s = 13

    Answer: 13 small frames, 9 Large frames
  2. 28 February, 16:13
    0
    9 large frames and 13 small frames

    Step-by-step explanation:

    Then number of each type can be found simultaneously by interpreting the given statements into equations. As such, if the number of the large frames and small frames purchased are a and b respectively. if she bought 22 frames then,

    a + b = 22

    Furthermore, if Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale for $239 then

    15a + 8b = 239

    solving both simultaneously,

    b = 22 - a

    15a + 8 (22 - a) = 239

    15a - 8a + 176 = 239

    7a = 239 - 176

    7a = 63

    a = 9

    b = 22 - 9

    = 13
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