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Isiah
Mathematics
18 January, 03:44
15x+31y=-3 x=-y+3
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Lyla Potts
18 January, 04:06
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15x + 31y = - 3
x = - y + 3
To solve this system, substitute - y + 3 into 15x + 31y = - 3 for x, and solve algebraically for y.
15x + 31y = - 3
15 (-y + 3) + 31y = - 3
-15y + 45 + 31y = - 3
16y + 45 = - 3
16y = - 48
y = - 3
Substitute - 3 for y into either of the original equations and solve algebraically for x.
x = - y + 3
x = - (-3) + 3
x = 3 + 3
x = 6
Finally, substitute both x - and y-values into both original equations to check work.
15x + 31y = - 3
15 (6) + 31 (-3) = - 3
90 + (-93) = - 3
-3 = - 3
6 = - (-3) + 3)
6 = 3 + 3
6 = 6
Answer:
x = 6
y = - 3
(6, - 3)
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