5x + 3y = - 2

3x + 2y = - 1

Solve the system of equations.

A) (-1, 1)

B) (1, - 1)

C) (-1, - 2)

D) (1/3, 1)

x = - 1, y = 1

Step-by-step explanation:

Solve the following system:

{5 x + 3 y = - 2 | (equation 1)

3 x + 2 y = - 1 | (equation 2)

Subtract 3/5 * (equation 1) from equation 2:

{5 x + 3 y = - 2 | (equation 1)

0 x+y/5 = 1/5 | (equation 2)

Multiply equation 2 by 5:

{5 x + 3 y = - 2 | (equation 1)

0 x+y = 1 | (equation 2)

Subtract 3 * (equation 2) from equation 1:

{5 x+0 y = - 5 | (equation 1)

0 x+y = 1 | (equation 2)

Divide equation 1 by 5:

{x+0 y = - 1 | (equation 1)

0 x+y = 1 | (equation 2)

Collect results:

Answer: {x = - 1, y = 1