Andrew solves 6x2=12x by using the quadratic formula. What values does he use for a, b, and c? a = (Put the number only in the blank - not the "a = ") b = (Put the number only in the blank - not the "b = ") c = (Put the number only in the blank - not the "c = ")

Question

Daniella Spencer

Mathematics

8 August, 11:14

Andrew solves 6x2=12x by using the quadratic formula. What values does he use for a, b, and c? a = (Put the number only in the blank - not the "a = ") b = (Put the number only in the blank - not the "b = ") c = (Put the number only in the blank - not the "c = ")

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Answers (1)

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Elian Gay · Answer 1

a=6, b=-12, and c=0

Step-by-step explanation:

The standard format for the quadratic formula is ax^2+bx+c (=0).

If we rearrange the numbers given to look like this formula, we will find the values of a, b, and c.

6x^2=12x We can move over the 12x to the other side.

6x^2-12x=0 There is no visible value of c, but since there is no term without a variable, c=0

6x^2-12x+0=0

So a=6, b=-12, and c=0