One day a toy store sold 3 xylophones and 3 yo-yos for $33. another day it sells 2 xylophones and 1 yo yo for $19. equations for the two days are 3x+3y=33 and 2x+y=19 where x is the value of one xylophone and y is the value of one yo-yo.

Question

Cannoli

Mathematics

21 July, 20:51

One day a toy store sold 3 xylophones and 3 yo-yos for $33. another day it sells 2 xylophones and 1 yo yo for $19. equations for the two days are 3x+3y=33 and 2x+y=19 where x is the value of one xylophone and y is the value of one yo-yo.

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Franklin Jackson · Answer 1

3x+3y=33 notice how in the bottom equation you can multiply y by 3 to get

2x+y=19 what is on top. This sets you up for an easy case of elimination! Multiply everything on the bottom by - 3 to start.

3x+3y=33 Then you can cross out the y's (because they're opposite) and

-6x-3y=-57 combine equations

-3x=-24 From there it is pretty straight forward to find x: Just divide - 24 by - 3

x=8 Then plug it back into any of your original equations and find y

3 (8) + 3y=33 You should find that y=3