Ask Question
6 February, 05:47

There are 13 animals in the barn. some are chickens and some are pigs. there are 40 legs in all. how many of each animal are there?

+2
Answers (2)
  1. 6 February, 05:52
    0
    Let p = pigs

    and c = chickens

    p + c = 13 (this is the total number of animals in the barn)

    chicken have 2 legs and pigs have 4 legs

    2c + 4p = 40 (this is the equation for the total number of legs)

    now lets solve for one variable using the first equation

    p+c = 13

    p = 13 - c

    now lets plug that in the 2nd equation

    2c+4p = 40

    2c + 4 (13-c) = 40

    2c + 52 - 4c = 40

    now we reduce

    -2c = - 12

    c = 6

    so there are 6 chickens now lets find how many pigs there are by plugging into our first equation

    p+6 = 13

    p = 7

    so there are 6 chickens and 7 pigs
  2. 6 February, 06:16
    0
    C=chicken

    p=pigs

    c+p=13~p=13-c (plug in)

    2c+4p=40

    2c+4 (13-c) = 40

    2c+52-4c=40

    -2c=-12

    c=6

    6+p=13

    p=7

    6 chickens

    7 pigs
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “There are 13 animals in the barn. some are chickens and some are pigs. there are 40 legs in all. how many of each animal are there? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers