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3 March, 03:14

The factors of 5y^2-2y-7 are (5y-7) and?

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  1. 3 March, 03:36
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    If we expand bx to jx and kx we have:

    5y^2-2y-7

    5y^2-7y+5y-7 then factor ...

    y (5y-7) + 1 (5y-7)

    (y+1) (5y-7)

    So the other factor is:

    (y+1)
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