At the end of a race a runner decelerates from a velocity of 8.00 m/s at a rate of 0.400 m/s2.

(a) How far does she travel in the next 15.0 s

75 m

Step-by-step explanation:

The formula to apply here is;

d (t) = v₀t + at²/2

where

d=distance covered in time t

v₀=initial velocity in m/s

t=time taken in seconds

a=deceleration

Given that

v₀=8.00 m/s

t=15 sec

a = - 0.400 m/s²

d (15) = 8.00 * 15 + (-0.400*15²) / 2

d (15) = 120 + - 90/2

d (15) = 120-45 = 75 m