2. When a person is selected at random from a very large population, the probability that the selected person is righthanded is 0.82. If three people are selected at random,

what is the probability that

a. They are all right-handed?

b. None of them is right-handed?

a) 0.5514

b) 0.0058

Step-by-step explanation:

Data provided in the question:

Probability that the the selected person is righthanded, P (R) = 0.82

Therefore,

Probability that the the selected person is not righthanded, P (R') = 1 - 0.82

= 0.18

Now,

a. They are all right-handed

P (They are all right-handed) = P (R) * P (R) * P (R)

= 0.82 * 0.82 * 0.82

= 0.5514

b) None of them is right-handed

P (None of them is right-handed) = P (R') * P (R') * P (R')

= 0.18 * 0.18 * 0.18

= 0.0058