The number of students enrolled in a new course as a function of time can be represented by the function.

f (x) = (4) x-1f (x) = (4) x-1

What is the average increase in the number of students enrolled per hour between hours 2 and 4?

Enter your answer in the box. Round to the nearest whole number

To solve the average increase between hours 2 and 4, first let as solve the the number of student in each hour

x = 2f (x) = 4x - 1f (2) = 4 (2) - 1f (2) = 7

x = 3f (x) = 4x - 1f (3) = 4 (3) - 1f (3) = 11

x = 4f (x) = 4x - 1f (4) = 4 (4) - 1f (4) = 15

increase in hours 2 to 4increase per hour = 15 - 7 / 4 - 2increase per hour = 4 students per hour