Paul started a construction company. In the first year, his company built 6 structures. The number of structures that his company built doubled every year.

How many total structures did Paul's company build by the end of the 5th year?

A.) 96

B.) 90

C.) 186

D.) 378

Question

Doogie

Mathematics

11 October, 21:41

Paul started a construction company. In the first year, his company built 6 structures. The number of structures that his company built doubled every year.

How many total structures did Paul's company build by the end of the 5th year?

A.) 96

B.) 90

C.) 186

D.) 378

+2

Answers (1)

Know the Answer?

Austin Matthews · Answer 1

For this case we have an equation of the form:

y = A (b) ^ x

Where,

A: initial amount

b: growth rate

x: time

Substituting we have:

y = 6 * (2) ^ (x-1)

For year 5 we have:

y = 6 * (2) ^ (5-1)

y = 96

Answer:

by the end of the 5th year Paul's company build:

A.) 96

Paul started a construction company. In the first year, his company built 6 structures. The number of structures that his company built doubled every year.How many total structures did Paul's company build by the end of the 5th year?A.) 96B.) 90C.) 186D.) 378

Paul started a construction company. In the first year, his company built 6 structures. The number of structures that his company built doubled every year.

How many total structures did Paul's company build by the end of the 5th year?

A.) 96

B.) 90

C.) 186

D.) 378