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27 October, 02:58

Find the perimeter of a rectangle of which length is 5 more than the width

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Answers (2)
  1. 27 October, 03:26
    0
    P = 4W + 10

    Step-by-step explanation:

    Perimeter is 2 * (length + width)

    let length be L and width be W

    if length is 5 more than width

    L = W + 5

    P = 2 (L + W)

    P = 2 (W + 5 + W)

    P = 2 (2W + 5)

    P = 4W + 10
  2. 27 October, 03:27
    0
    the perimeter = 10+4W.

    where W = the width.

    Step-by-step explanation:

    mathematically, perimeter (p) = 2L + 2W

    where L = length. and W=width

    from the expression; length is 5 more than the width

    it is written as L = 5+W

    substitute in the formula

    P = 2 (5+W) + 2W

    P=10+2W+2W

    P=10+4W as the perimeter of the rectangle.
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