When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 58%?

a. 0.21b. 0.42c. 0.58d. 0.79

The awnser on edge is A) 0.21

When confidence level c is given to us then the critical probability for finding Margin of error is

α/2 which is evenly distributed at the both ends of Normal curve

Where α = 1 - c

Here we have given confidence level = 58%

It means c = 58 / 100 = 0.58

α = 1 - c

α = 1 - 0.58

α = 0.42

Now the critical probability while finding margin of error is

α/2 = 0.42/2 = 0.21

The critical probability is a. 0.21