Frank stands 450 feet from the base of the Statue of Liberty. If the Statue of Liberty is 306 feet tall, what is the angle of depression from the top of the statue's torch to Frank? Round the answer to the nearest tenth.

a.

33.7°

b.

34.2°

c.

55.8°

d.

56.3°

Question

Alisson Baker

Mathematics

9 October, 02:57

Frank stands 450 feet from the base of the Statue of Liberty. If the Statue of Liberty is 306 feet tall, what is the angle of depression from the top of the statue's torch to Frank? Round the answer to the nearest tenth.

a.

33.7°

b.

34.2°

c.

55.8°

d.

56.3°

+2

Answers (1)

Know the Answer?

Luca Solomon · Answer 1

The angle of depression is also equal to the angle of elevation (at least in terms of magnitude) so:

tanα=306/450

α=arctan (306/450)

α≈34.2° (to nearest tenth of a degree)

Frank stands 450 feet from the base of the Statue of Liberty. If the Statue of Liberty is 306 feet tall, what is the angle of depression from the top of the statue's torch to Frank? Round the answer to the nearest tenth.a.33.7°b.34.2°c.55.8°d.56.3°

Frank stands 450 feet from the base of the Statue of Liberty. If the Statue of Liberty is 306 feet tall, what is the angle of depression from the top of the statue's torch to Frank? Round the answer to the nearest tenth.

a.

33.7°

b.

34.2°

c.

55.8°

d.

56.3°