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22 November, 01:36

Select all of the following that are quadratic equations.

x2 - 2x = 4x + 1

x3 - 6x2 + 8 = 0

5x - 3 = 0

2x2 + 12x = 0

5x - 1 = 3x + 8

9x2 + 6x - 3 = 0

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Answers (1)
  1. 22 November, 01:37
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    What you want to do is solve all of these so that it equals to 0 on one side. The ones that are a quadratic will have x^2

    x^2 - 2x = 4x + 1

    x^2 - 6x - 1 = 0

    Yes this is a quadratic

    x^3 - 6x^2 + 8 = 0

    No this is not a quadratic because the highest power of x is to the power of 3

    5x - 3 = 0

    No it is not a quadratic because it does not have x^2

    2x^2 + 12x = 0

    Yes because there's x^2

    5x - 1 = 3x + 8

    2x - 9 = 0

    No because no x^2

    9x^2 + 6x - 3 = 0

    Yes because there's x^2
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