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4 April, 15:48

What is the inverse of the function f (x) = - 5x^2 3, for x>or equal to 0?

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  1. 4 April, 16:01
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    F (x) = - 5x^2 + 3

    y = - 5x^2 + 3

    5x^2 = 3 - y

    x^2 = (3 - y) / 5

    x = sqrt ((3 - y) / 5)

    Therefore, f^-1 (x) = sqrt ((3 - x) / 5)
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