A yoga studio offers memberships that cost $60 per month for unlimited classes. The studio also accepts walk-ins, charging $6 per class. If someone attends enough classes in a month, the two options cost the same total amount. How many classes is that?

Question

Davin Burgess

Mathematics

12 February, 21:36

A yoga studio offers memberships that cost $60 per month for unlimited classes. The studio also accepts walk-ins, charging $6 per class. If someone attends enough classes in a month, the two options cost the same total amount. How many classes is that?

+4

Answers (2)

Know the Answer?

Johan Woodward · Answer 1

210 is the answer

Step-by-step explanation:

So if you want to find the total cost (c) for a certain number of months (m) and it costs $35 per month, you just need to multiply the number of months by the cost per month. So

35m=c

If you want to see the units cancel

($35/month) (months) = $

The months will cancel out, and you will be left with total dollars.

Not sure about the second part of your question, but if you wanted to figure out how much it would cost to be a member for 6 months, you would just plug in 6 for m.

35 (6) = c

c=210

So $210

Ernest Webb · Answer 2

10 classes

Step-by-step explanation:

Ok, so to solve this we have to make two different equations. we can say 60x = y, or $60 per month, and 6a = b, or $6 per walk in. Since we want the options to end up costing the same, we can say that y = b. With substitution, we get that 60x, (60 per month) = 6a (6 per drop in). The question says we have 1 month, so x = 1. This means we have 60 = 6a, and a = 10 (10 classes).