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4 September, 11:30

A total of $6000 $6000 is invested: part at 8% 8% and the remainder at 13% 13%. how much is invested at each rate if the annual interest is $650 $650?

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  1. 4 September, 11:47
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    0.13x + 0.08 (6000-x) = 650 Solve for x
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