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20 November, 04:16

Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = - 226

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  1. 20 November, 04:34
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    First determine the common difference by the equation,

    d = (an - a1) / (n - 1)

    Using the given values,

    d = (-226 - 26) / (22 - 1) = - 12

    Then, determine the 31st term,

    a31 = a1 + (31 - 1) x (d)

    Substituting,

    a31 = 26 + (30) (-12) = - 334

    Therefore, the 31st term is - 334.
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