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9 June, 23:01

How do you solve 4b^2+8b+-12=0. Also find the parabole.?

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  1. 9 June, 23:20
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    First you divide everything by 4 which will become b^2+2b-3=0

    Then you can factor this which is

    (b-1) (b+3) = 0

    B=1

    B=-3 ... I think that's how you do it
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