Determine the required value of the missing probability to make the distribution a discrete probability distribution. x p (x) 3 0.290.29 4 ? 5 0.320.32 6 0.220.22

The Given is:

P (3) = 0.29

P (5) = 0.32

P (6) = 0.22

The solution will be:

P (4) = 1 - P (3) - P (5) - P (6)

= 1 - 0.29 - 0.32 - 0.22

= 0.17

P (4) is equal to 0.17 according to our simple computation.