Find the range of the function below if the domain is {-1,0,2}

f (x) = x^2 - 2x + 3

{3, 6}

Step-by-step explanation:

f (x) is the same thing as y. f (x) or y are the values that are shown in the range.

The domain represents all possible values of x. Data must be in an (x, y) form, where any value of "y" would need a partner, "x".

Substitute all of the possible x-values into the formula to find all possible y-values (the range).

f (x) = x² - 2x + 3

f (-1) = (-1) ² - 2 (-1) + 3

f (-1) = 1 + 2 + 3

f (-1) = 6

f (x) = x² - 2x + 3

f (0) = (0) ² - 2 (0) + 3

f (0) = 0 - 0 + 3

f (0) = 3

f (x) = x² - 2x + 3

f (2) = (2) ² - 2 (2) + 3

f (2) = 4 - 4 + 3

f (2) = 3 Do not write repeated numbers

The possible y-values are 3 and 6.

Writ the range in set notation in the brackets {}. Order the numbers from least to greatest.

Range is {3, 6}.