The length of a rectangle is 6m longer than its width. If the perimeter of the rectangle is 52m, find its area

Question

Stanley Reese

Mathematics

13 October, 17:56

The length of a rectangle is 6m longer than its width. If the perimeter of the rectangle is 52m, find its area

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Answers (1)

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Logan Cervantes · Answer 1

If length is x, then width is 6+x

Perimeter = 2 * (x + 6+x) = 52

2*6 + 2*2x = 52

4x = 52 - 12 = 40

x = 40/4 = 10

Area = length*width = 10 * (6+10)

Area = 10*16 = 160 meter square