Given that z is a standard normal random variable, find z for each situation (to 2 decimals).

a. The area to the left of z is. 9738

b. The area between 0 and z is. 4738 (is positive).

c. The area to the left of z is. 8531

d. The area to the right of z is. 1251

e. The area to the left of z is. 6700

f. The area to the right of z is. 3300

a. 1.94

b. 1.94

c. 1.05

d. 1.15

e. 0.44

f. 0.44

Step-by-step explanation:

z-table is used to calculate the values

a. The area to the left of z is. 9738

z = 1.94

b. The area between 0 and z is. 4738 (is positive)

z = 1.94

c. The area to the left of z is. 8531

z=1.05

d. The area to the right of z is. 1251

z=1.15

e. The area to the left of z is. 6700

z=0.44

f. The area to the right of z is. 3300

z=0.44