Consider the sets below. U = {x / x is a real number}

A = x is an odd integer

R = x

Is RCA?

O

yes, because all the elements of set A are in set R

yes, because all the elements of set Rare in set A

no, because each element in set A is not represented in set R

no, because each element in set R is not represented in set A

O

Step-by-step explanation:

answer is b

R ⊂ A yes, because all the elements of set R are in set A.

Step-by-step explanation:

U = {x / x is a real number}

A = x is an odd integer

R = x = 3, 7, 11, 27

Now, here The elements in the set A = { 1, 3, 5, 7, 9, 11, ... }

The elements in the set R = { 3, 7, 11, 27}

A set P is said to be be contained in a set Q if all the elements of P are also the element of the set Q.

or, P⊂ Q ⇔ all elements of P are also the set Q

Here, R = { 3, 7, 11, 27} is contained in the set A = { 1, 3, 5, 7, 9, 11, ... }

⇒ All the elements of R are also the elements of the set A.

Hence, R ⊂ A yes, because all the elements of set R are in set A.