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27 June, 12:16

A commuter railway has 800 passengers a day and charges each one 2 dollars.?

For each 10 cents the fair is increased, 2 fewer people will ride the train. Express the income I from the train in terms of the ticket price p (in dollars). T/F

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  1. 27 June, 12:45
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    I = - 20p^2 + 840p

    Step-by-step explanation:

    When the ticket price is $2 there are 800 passengers daily, but every $0.1 increase in ticket price the number of passengers will be decreased by 2.

    You can put information into these equations of:

    passenger - = (800-2x)

    ticket price = p = $2 + 0.1x

    Income is calculated by multiplying the number of the passenger with the ticket price. The answer will be expressed in terms of the ticket price, so we need to remove x from the passenger equation.

    p = $2 + 0.1x

    p-$2 = 0.1x

    x = 10p - $20

    If p = ticket price, the function for the number of passengers it will be:

    passenger = (800-2x)

    passenger = 800 - 2 (10p - $20)

    passenger = 800 - 20p+40

    passenger = 840 - 20p

    The function of I will be:

    I = passenger x ticket price

    I = 840 - 20p * p

    I = - 20p^2 + 840p
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