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Delaney Mendez
Mathematics
21 April, 11:58
How do I solve (5x-7) (3x-8) ?
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America Montes
21 April, 12:23
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(5x-7) (3x-8)
Expand using FOIL (multiply the firsts, then outers, then inners, then lasts):
Firsts: 5x * 3x = 15x²
Outers: 5x * - 8 = - 40x
Inners: - 7 * 3x = - 21x
Lasts: - 7 * - 8 = 56
Combine them all together:
15x² - 40x - 21x + 56
15x^2 - 61x + 56
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