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10 January, 04:59

A screen door spring has a spring constant of 188 N/m, and stretches 0.292 m when the door is opened. What force does it exert?

(Unit = N)

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Answers (2)
  1. 10 January, 05:07
    0
    54.846N

    Step-by-step explanation:

    Force = ?

    Spring constant (K) = 188N/m

    Spring stretch (x) = 0.292m

    Force acting on a spring = spring constant * spring stretch

    Force = 188 * 0.292

    Force = 54.896N

    The force acting on the spring is 54.896N
  2. 10 January, 05:14
    0
    The answer is 54.896N

    Step-by-step explanation:

    From Hooke's law,

    Force = spring constant x extension

    i. e

    F = k x e

    F = 188N/m x 0.292m

    F = 54.896N
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