Ask Question
29 April, 16:16

The width of a rectangle is 4 inches less than the length, the perimeter is 48, what is the dimensions?

+3
Answers (2)
  1. 29 April, 16:23
    0
    Answer: 10 inches * 14 inches

    Work:

    length = x inches

    width = x - 4 inches

    perimeter = 2 (l+w)

    48 = 2[ (x) + (x - 4) ]

    48 = 2 (2x - 4)

    24 = 2x - 4

    28 = 2x

    14 = x

    length = x inches = 14 inches

    width = x - 4 inches = 14 - 4 = 10 inches
  2. 29 April, 16:23
    0
    Length is 14 inches, width is 10 inches.

    If you need area, it's 140 inches.

    2L + 2w = 48

    L = w + 4

    2 (w+4) + 2w = 48

    2w + 8 + 2w = 48

    4w + 8 = 48

    4w = 40

    w = 10

    L = w + 4

    L = 10 + 4

    L = 14
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The width of a rectangle is 4 inches less than the length, the perimeter is 48, what is the dimensions? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers