Employees at a company constantly reorganize and reshelve merchandise. In doing so, they calculate floor space needed for displays. The algebraic expression ltimesw gives the floor space needed in square units for a display that measures length l units and width w units. Calculate the floor space needed for a display whose length is 4.7 feet and whose width is 6 feet.

Question

Maci Buck

Mathematics

3 October, 02:14

Employees at a company constantly reorganize and reshelve merchandise. In doing so, they calculate floor space needed for displays. The algebraic expression ltimesw gives the floor space needed in square units for a display that measures length l units and width w units. Calculate the floor space needed for a display whose length is 4.7 feet and whose width is 6 feet.

+3

Answers (1)

Know the Answer?

Blimpie · Answer 1

28.2 ft²

Step-by-step explanation:

Data provided in the question:

Length of the display floor, l = 4.7 feet

Width of the display floor, w = 6 feet

Therefore,

The area of the floor space = l * w

on substituting the value in the above formula,

The area of the floor space = 4.7 * 6

or

The area of the floor space = 28.2 ft²

Hence, the floor space needed for the display is 28.2 ft²