Two consecutive integers have sum of 137

You would do x + (x+1) = 137

2x+1=137

Subtract 1 from each side

2x=136

x=68.

Add 1 to 68, since they are consecutive integers.

The answer is 68 and 69

Here's how you approach a problem of this nature in general:

Let x be the lower of the two integers.

Then (x+2) is the other integer

and x + (x+2) = 137

2x + 2 = 137

2x = 135

x = 67.5 - which isn't an integer, of course, but we already knew there was no solution to this problem!