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26 June, 03:22

Given h (x) = √5-x, the range of h, in inequality notation, is

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  1. 26 June, 03:46
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    Assuming that the 5-x is under te sqrt sign

    you cannot have sqrt of a negative

    find where it equals zero

    5-x=0

    5=x

    the limit is 5=x

    x has to be greater than x

    to infinity

    D=x>5
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