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21 March, 09:55

A local basketball court dimensions are 50 ft long, 20 ft wide, the court is lost square footage by 1/4. what are the new dimensions of the court. write the equation out then solve.

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  1. 21 March, 10:23
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    50x20=1000

    1000x (1/4) = 250

    1000-250=750ft^2
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