The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3. Suppose a golfer played the course today. Find the probability that her score is at least 74.

0.3694

Step-by-step explanation:

In this question, we are asked to calculate the probability that a golfer scored at least 74 if she played on a particular day.

Given that,

mean = µ = 73

standard deviation = σ = 3

P (x > 74) = 1 - P (x<74)

= 1 - P[ (x - µ) / σ < (74 - 73) / 3 ]

= 1 - P (z <0.3333)

Using z table

= 1 - 0.6305

= 0.3694

probability = 0.3694