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18 August, 20:36

If p (x) = 5 (x^2+1) + 16 what is the value of p (11)

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  1. 18 August, 20:53
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    5 (11^2+1) + 16

    5 (121+1) + 16

    5 (122) + 16

    610+16

    p (11) = 626
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