Suppose that circles A and B have a central angle measuring 40°. Additionally, circle A has a radius of

5/2 ft and the radius of circle B is

9 / 2 ft.

If the measure of the sector for circle A is 25/36 π ft2, what is the measure of the sector for circle B?

A)

2

9

π ft2

B)

4

9

π ft2

C)

9

4

π ft2

D)

9

2

π ft2

Question

David Schmitt

Mathematics

12 January, 14:37

Suppose that circles A and B have a central angle measuring 40°. Additionally, circle A has a radius of

5/2 ft and the radius of circle B is

9 / 2 ft.

If the measure of the sector for circle A is 25/36 π ft2, what is the measure of the sector for circle B?

A)

2

9

π ft2

B)

4

9

π ft2

C)

9

4

π ft2

D)

9

2

π ft2

+5

Answers (1)

Know the Answer?

Josh Guerra · Answer 1

The measure of the sector of circle B is given by:

A=θ/360πr²

But

θ=40°

r=9/2 ft

thus

A=40/360*π * (9/2) ²

A = (9π) / 4 ft²

Answer: C] (9π) / 4 ft²

Suppose that circles A and B have a central angle measuring 40°. Additionally, circle A has a radius of5/2 ft and the radius of circle B is9 / 2 ft.If the measure of the sector for circle A is 25/36 π ft2, what is the measure of the sector for circle B?A)29π ft2B)49π ft2C)94π ft2D)92π ft2