3 February, 04:24
What is the vertex f (x) = 5x^2+20x-16
3 February, 05:22
F (x) = 5x² + 20x - 16
y = 5 (x² + 4x) - 16
y + 16 = 5 (x² + 4x + __)
x² ⇒ x * x
4x ⇒ 2*2x
2² = 4
y + 16 + 4 = 5 (x² + 4x + 4)
y + 20 = 5 (x+2) ²
(x+2) ² ⇒ (x+2) (x+2) = x (x+2) + 2 (x+2) = x² + 2x + 2x + 4 = x² + 4x + 4
y = 5 (x+2) ² - 20
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