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7 January, 00:13

An adult consumes an espresso containing 60 mg of caffeine. If the caffeine has a half-life of 5.5 hours, when will the amount of caffeine in her bloodstream equal 30 mg? Create an exponential model for the given situation. Use the exact value for k in the function.

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  1. 7 January, 00:32
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    since the caffeine concentration drops to half, the time required is the half-life = 5.5 hours

    Step-by-step explanation:

    if we use an exponential model

    C (t) = C (0) * e^ (-kt)

    where

    C (t) = concentration at time t

    C (0) = concentration at time t=0

    k = characteristic parameter

    then, when the caffeine concentration reaches half-life (t=th), the concentration will be half of the initial, therefore

    C (t) = C (0) / 2 = C (0) * e^ (-kT)

    - ln 2 = - th*k

    k = ln (2) / th

    then when the concentration reaches C₁=30 mg

    C₁ = C (0) * e^ (-kt)

    t = ln [C (0) / C₁] / k = [ln [C (0) / C₁] / ln (2) ] * th

    replacing values

    t = [ln [C (0) / C₁] / ln (2) ] * th = [ln [60 mg / 30 mg] / ln (2) ] * 5.5 hours = 5.5 hours

    since the caffeine concentration drops to half, the time required is the half-life = 5.5
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