Find the zeros of x^2+4x=-10 using the quadratic formula

X^2+4+10=0

x = (-4 (+/-) root16-40) / 2, so we now know that the zeros are imaginary, because you can't square root a negative number and 16-40 is - 24

so the two roots are ...

-2+iroot6 and - 2-iroot6

X² + 4x = 10

x² + 4x - 10 = 10 - 10

x² + 4x - 10 = 0

x = - 4 + / - √ (4² - 4 (1) (-10))

2 (1)

x = - 4 + / - √ (16 + 40)

2

x = - 4 + / √56

2

x = - 4 + / - √ (4 * 14)

2

x = - 4 + / - √4 √14

2

x = - 4 + / - 2√14

2

x = - 4 + / - 2 (3.741657387)

2

x = - 4 + / - 7.483314774

2

x = - 4 + 7.483314774 x = - 4 - 7.483314774

2 2

x = 3.483314774 x = - 11.483314774

2 2

x = 1.741657387 x = - 5.741657387