What is the value for x in this equation?

log (6x + 5) - log2 = log5

Log (6x+5) - log2=log 5

log (6x+5) = log 5+log 2

log 5 = 0.698970004 ...

log 2=0.301029995

log 5 + log 2=1

log (6x+5) = 1

log (6x+5) = log 10

Then:

6x+5=10

6x=10-5

6x=5

x=5/6

Answer: the value for x in this equation is 5/6.