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12 January, 00:55

What is the value of k in the function ƒ (x) = 112 - kx if ƒ (-3) = 121? k = a0

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  1. 12 January, 01:21
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    F (x) = 112 - kx

    f (-3) = 121

    f (-3) = 112 - k (-3)

    f (-3) = 112 + 3k

    121 = 112 + 3k

    121 - 112 = 3k

    9 = 3k

    9/3 = k

    3 = k <===
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